Respuesta :

plbak

Hello!

√28x³y³ is equal to [tex]2xy\sqrt{7xy}[/tex]

We can find this solution through the following steps.

  1. Rewriting the equation by factoring 4 from 28, factoring out x², and factoring out y²
  2. We then can rewrite 4 as 2² in our equation, leaving us with [tex]\sqrt{2^{2}*7*(x^{2}x)*y^{2}y }[/tex]
  3. We will then move our x and 7, and rewrite [tex]2^{2}*x^{2}* y^{2}[/tex] as [tex](2xy)^{2}[/tex]
  4. We can then pull the terms from the radical leaving us with [tex]2xy\sqrt{7xy}[/tex]

Otras preguntas