The "Ideal Gas Law Equations" is [tex]PV=nRT[/tex] P= Pressure (in Pascals) V=Volume (in Liters) n=amount, or number (in moles) R= 8.3145 [tex] \frac{Pascals*Liters}{Moles*Kelvin} [/tex] or [tex] \frac{PaL}{molK} [/tex] T= Temperature (In Kelvin)
[tex]P= \frac{nRT}{V} [/tex]
Plug into the equation and you're good! [tex] P=\frac{nRT}{V} [/tex] [tex]P =\frac{(5mol)(8.3145)(286K)}{2L} [/tex] [tex]P=5944.8675Pa[/tex]
If your teacher cares about sig figs, 2 sig figs (significant figures) [tex]P=5900Pa[/tex]
For other units of pressure, 1 atm = 760 mmHG = 760 Torr = 101326 Pa = 1.01325 bar
