a bionic man running at 6.5 m/sec , east is acceleration at a uniform rate of 1.5 m/sec^2 east over a displacement of 100.0 m east . what is the velocity he reaches after traveling this displacement
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Given: u = 6.5 m/s, initial velocity a = 1.5 m/s², acceleration s = 100.0 m, displacement
Let v = the velocity attained after the 100 m displacement. Use the formula v² = u² + 2as v² = (6.5 m/s)² + 2*(1.5 m/s²)*(100 m) = 342.25 (m/s)² v = 18.5 m/s
